[Abaqus 03. 예제 - 기둥] 편심하중 정적선형 응력해석(cae,inp)
작성자 : kim2kie
(2023-02-12)
조회수 : 15034
[참조]
Applying an Eccentric Load using the Coupling Constraint, 2022
https://www.youtube.com/watch?v=z9L0KKZjDf4
(1) Part
(2) Property
(3) Assembly
(4) Step
(5) Interaction
(6) Load
(7) Mesh
(8) Job
(9) Visualization
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[문제]
단주의 응력을 구하라.
.단위: m, kg(자중은 무시), N
.rho = 7,800e-12 t/mm^3, E = 200,000 MPa, nu = 0.3, P = 4.8 kN
(1) Part
.extrusion으로 solid box를 작성
(2) Property
.part에 propety를 할당
(3) Assembly
.part를 instance(실체)로 조립
.set를 정의
(4) Step
.Step-1: General > Static, General nfreq : Increment size = 0.1
.Field Output: U, Translations and rotations
(5) Interaction
.RP(reference point)
.Constraint
(6) Load
.Load: Step-1
.BC: Initial
(7) Mesh
.Seed
.Mesh
(8) Job
.Create Job
(9) Visualization
.Create XY Data > Unique Nodal > Stres Components : S33
.XY Data manager
.수치해 vs 이론해